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Simplifying b2c2 + 18bc + 81 = 0 Reorder the terms: 81 + 18bc + b2c2 = 0 Solving 81 + 18bc + b2c2 = 0 Solving for variable 'b'. Factor a trinomial. (9 + bc)(9 + bc) = 0Subproblem 1
Set the factor '(9 + bc)' equal to zero and attempt to solve: Simplifying 9 + bc = 0 Solving 9 + bc = 0 Move all terms containing b to the left, all other terms to the right. Add '-9' to each side of the equation. 9 + -9 + bc = 0 + -9 Combine like terms: 9 + -9 = 0 0 + bc = 0 + -9 bc = 0 + -9 Combine like terms: 0 + -9 = -9 bc = -9 Divide each side by 'c'. b = -9c-1 Simplifying b = -9c-1Subproblem 2
Set the factor '(9 + bc)' equal to zero and attempt to solve: Simplifying 9 + bc = 0 Solving 9 + bc = 0 Move all terms containing b to the left, all other terms to the right. Add '-9' to each side of the equation. 9 + -9 + bc = 0 + -9 Combine like terms: 9 + -9 = 0 0 + bc = 0 + -9 bc = 0 + -9 Combine like terms: 0 + -9 = -9 bc = -9 Divide each side by 'c'. b = -9c-1 Simplifying b = -9c-1Solution
b = {-9c-1, -9c-1}
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